2.5 Exponent Laws: Part 2
In this lesson, we will practice using the exponent laws to simplify more complicated expressions.
Simplifying Expressions with Coefficients
Example 1
Simplify 3m3
4m5.
| Steps | Solution |
|---|---|
| Rearrange the expression to put coefficients with coefficients and variables with variables. | 3m3 (3)(4)(m3 )(m5) |
| Multiply the coefficients, and use the Product Law to simplify the variables. | 12m8 |
Practice 1
Simplify.
| a) (12x3)(4x5)
|
b) (–5m9)(–5m8)
|
c) p3q2p4q
|
| d) –2n3
|
e) 3x2y3
|
Example 2
Simplify ![]()
| Steps | Solution |
|---|---|
| Rewrite the expression to put the coefficients together as one fraction and the variables together as one fraction. |
|
| Divide the coefficients, and use the Quotient Law to simplify the variables. | 2a3 |
Practice 2
Simplify.
| a)
|
b)
|
c)
|
| d)
|
e)
|
Simplifying Expressions with Two or More Exponent Laws
To simplify some expressions, you will need to use two or more exponent laws.
Practice 3
Simplify.
| a) (4p5)2
|
b) (–3x4y5)3
|
c)
|
d)
|
Practice 4
Simplify.
| a) –7x3y6(2x2y2)4
|
b) (3r2s4)2(4r3s5)2
|
| c)
|
d)
|
Practice 5
Simplify.
| a) (2a2a4b5)3(–5b4b2)2
|
b)
|
c)
|
Homework
-
Simplify.
a)
b)
c)
d)
e)
f)
g)
h)
-
Simplify.
a)
b)
c)
d)
e)
f)
g)
h)
-
Simplify.
a)
b)
c)
d)
e)
f)
-
When Paula simplified
and
, she got the same answer. Explain how using the Order of Operations correctly gives different answers.
Answers
1.
| a) |
b) |
c) |
d) |
| e) |
f) |
g) |
h) |
2.
| a) |
b) |
c) |
d) |
| e) |
f) |
g) |
h) |
3.
| a) |
b) |
c) |
d) |
e) |
f) |
4. 30 = 1, then multiplying by –1 gives you –3. On the other hand, (–3)0 = 1.
Attribution
Unless otherwise indicated, material on this page has been adapted from the following resource:
Mazur, I. (2021). Introductory algebra. BCcampus. https://collection.bccampus.ca/textbooks/intermediate-algebra-bccampus-412/, licensed under CC BY 4.0